7x^2+8x+1=(7x+1)(x+1)

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Solution for 7x^2+8x+1=(7x+1)(x+1) equation: 



7x^2+8x+1=(7x+1)(x+1)

We move all terms to the left:

7x^2+8x+1-((7x+1)(x+1))=0

We multiply parentheses ..

7x^2-((+7x^2+7x+x+1))+8x+1=0



We calculate terms in parentheses: -((+7x^2+7x+x+1)), so:

(+7x^2+7x+x+1)

We get rid of parentheses

7x^2+7x+x+1

We add all the numbers together, and all the variables

7x^2+8x+1

Back to the equation:

-(7x^2+8x+1)



We add all the numbers together, and all the variables

7x^2+8x-(7x^2+8x+1)+1=0

We get rid of parentheses

7x^2-7x^2+8x-8x-1+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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